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3 years ago

What are some characteristics of microbes and infectious agents that would require handling in a BSL-3 laboratory?

Biology

2 answers:

Inga [223]3 years ago

8 0

Answer:

BSL or the biological safety levels refers to an array of protections consigned to autoclave-associated activities, which occurs in specific biological labs. The BSL-3 refers to the biosafety level that generally comprises work on microbes, which are either exotic or indigenous and can result in potentially or extreme lethal disease via inhalation. The examples of microorganisms that are handled in BSL=3 comprises West Nile virus, yellow fever, and the bacteria, which leads to tuberculosis.

andreev551 [17]3 years ago

3 0

Answer:

Explanation:

The microbes would be toxic or have potential to cause a lethal disease.
Highly infectious, like Mycobacterium tuberculosis which is readily and highly transmitted by inhalation and aerosol means.
Can contaminate the environment.
The treatment or prophylactic measures are expensive and inefficient.

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Do predators really kill only the old and sick prey? What evidence is there for this system

Mekhanik [1.2K]

Yes the weaker it is the more easy it is to prey on

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3 years ago

What is the role of renin in the secretion of aldosterone?

Gelneren [198K]

Answer:

Explanation:

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2 years ago

Which strand of mRNA would be made during transcription using the DNA strand shown below?

GrogVix [38]

Answer:

b GAC TAT

Explanation:

ATGC = TACG

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3 years ago

1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently

maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

Available data:

Flower position: Axial (A) is dominant to Terminal (a)

Stem length: Tall (T) is dominant to dwarf (t)

Seed shape: Round (R) is dominant to wrinkled (r)

Cross:

Parental) AaTtDd x AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

AA= 1/4

Aa =2/4

aa = 1/4

TT = 1/4

Tt = 2/4

tt = 1/4

DD = 1/4

Dd = 2/4

dd = 1/4

This is the same as developing a Punnett square for each gene separately.

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4 x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0

3 years ago

Read 2 more answers

Explain when both the processes of mitosis and meiosis are performed in a multicellular organism.

fiasKO [112]

The processes of mitosis and meiosis performed in a multicellular organism are mitosis creates indentical genetic copies of cells and meiosis creates haploid gametes. this is what make multicelllar organisms grow larger and repair damage.

hope this help

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3 years ago