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vova2212 [387]
3 years ago
11

How much wrapping paper do you need to completely cover a rectangular box that is 20 inches by 18 inches by 2 inches?

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0
872in²
You use the formula A=2(wl+hl+hw)
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2(3x+2)=2x-1+x solve
alina1380 [7]
First multiply and dstribute
a(b+c)=ab+ac
2(3x+2)=6x+4
6x+4=2x-1+x
add like terms
6x+4=3x-1
subtract 3x from both sides
3x+4=-1
subtract 4 from both sides
3x=-5
divide bothe sides by 3
x=-5/3
7 0
3 years ago
Arrange these fractions in ascending order: 3/4, 2/5, 3/8, 7/10, 11/20, 23/40. Please help it’s due tomorrow and I’m big dumb
disa [49]

Answer:

3/8, 2/5, 11/20, 23/40, 7/10, 3/4

Step-by-step explanation:

Just change them all to the same denominator and you're good. Put all of the fractions' denominators to 40 as that's the least common denominator. 3/4 turns into 30/40. 2/5 turns into 16/40. 3/8 turns into 15/40. 7/10 turns into 28/40. 11/20 turns into 22/40. And 23/40 stays as it is, because the denominator is already 40.

Putting them in order is now simple,

3/8 (15/40) <  2/5 (16/40) < 11/20 (22/40) < 23/40 < 7/10 (28/40) < 3/4 (30/40)

***When you multiply any fraction to change its denominator, multiply it by the same thing to the numerator as well.

Good Luck!

8 0
3 years ago
297 words in 5.5 minutes ? im confused again
Vedmedyk [2.9K]

Answer:

The unit rate of 297 words for 5.5 minutes is, 54 words per minutes

hope this helps :-)

5 0
3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
What are the x-intercepts for the function below? y= (x – 3) (x + 7)<br>​
antoniya [11.8K]

Answer:

x-intercept(s): (3,0) and (-7,0)

(y intercepts- (0,-21)

Step-by-step explanation:

4 0
2 years ago
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