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Vadim26 [7]
3 years ago
9

there are 12 students sharing pants. Each student needs 1/3 a can of paint to finish their project. How many whole cans of paint

are needed?
Mathematics
2 answers:
Sliva [168]3 years ago
6 0
If there are 12 students sharing plants and each student need 1/3 of a can, they only need 4 cans for all 12 students!!
xz_007 [3.2K]3 years ago
5 0

Answer:

4 cans of paint are needed.  

Step-by-step explanation:

\frac{12}{1} *\frac{1}{3} =\frac{12}{3} = 4

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anyanavicka [17]

Answer:

58

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A large group of students took a test in Physics and the final grades have a mean of 70 and a standard deviation of 10. If we ca
Sholpan [36]

Answer:

The scores are between 50 and 90

Step-by-step explanation:

When we say middle 95%, we means that this value falls between 2 standard deviations of the mean i.e

μ ± 2σ

Hence,

mean of 70 and a standard deviation of 10

μ ± 2σ

μ - 2σ

70 - (2 × 10)

= 70 - 20

= 50

μ + 2σ

= 70 + (2 × 10)

= 70 + 20

= 90

4 0
3 years ago
Una empresa fabrica dos modelos de DVD: el modelo A y el modelo B. Se dispone de 50 kilogramos de caucho y de 80 horas de mano d
alexandr1967 [171]

Answer:

¿Cuántos DVD de cada tipo debe fabricar y vender para que la utilidad sea máxima?

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800

Step-by-step explanation:

x : Número de DVD del modelo A

y : Número de DVD del modelo B.

                               MODELO A MODELO B TOTAL

Cantidad de caucho                  1x 1x                 50 kg.

Horas de mano de obra           1x 2x                 80 horas

U : Utilidad mensual.

La función objetivo, que se debe maximizar, es:

U=30   + 40y

x+ y \leq 50\\  

x + 2y \leq 80

x\geq 0

y\geq 0

Las coordenadas de los vértices de la región factibles son:

A (0, 0) B (50, 0) C (20, 30) D(0, 40)

Entonces, se evalúa la función objetivo en cada punto:

U (0, 0) = 30 (0) + 40 (0) = 0

U (50, 0) = 30 (50) + 40(0) = 1500

U (90, 0) = 30 (20) + 40 (30) = 1800

U (0, 40) = 30 (0) + 40 (40) =1600

Por consiguiente U tiene un valor máximo en C , en donde: x =20 ,  y = 30 .

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800.

 

 30 x  40 y

 

s.a.

 



   x  0 (3)

 

  y  0 (4)

3 0
3 years ago
PLEASEEE HURRY !!!
Morgarella [4.7K]

Answer:

b : $0.22 on edg.

Step-by-step explanation:

7 0
3 years ago
Suppose that is an angleand y is not in the first quadrant. Compute the exact value of secyYou do not have to rationalize the de
Pavel [41]

ANSWER :

The answer is :

-\frac{5\sqrt{10}}{9}

EXPLANATION :

Note that cotangent is only positive when the angle is in the first or third quadrant.

Since y is not in the first quadrant, it must be in the third quadrant.

So the x and y are both negative.

An angle with a terminal point (x, y)

The cotangent is x/y

We can equate :

\cot\gamma=\frac{9}{13}=\frac{x}{y}

Since x and y are both negatives, x = -9 and y = -13

We can have the triangle :

The hypotenuse will be :

\begin{gathered} c=\sqrt{(-9)^2+(-13)^2} \\ c=5\sqrt{10} \end{gathered}

We are asked to find the value of sec y.

In an angle with a terminal point (x, y)

The secant is :

\sec\gamma=\frac{\text{ hypotenuse}}{x}

The hypotenuse is 5√10 and x = -9

The value of sec will be :

\begin{gathered} \sec\gamma=\frac{5\sqrt{10}}{-9} \\  \\ =-\frac{5\sqrt{10}}{9} \end{gathered}

6 0
1 year ago
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