What is the slope of the line given by the equation y-9=15(x-5) ?

Find the equation of this line. HELP

Mumz [18]

Answer:

Step-by-step explanation:

(5,4) ; (-3, -2)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-4}{-3-5}\\\\=\frac{-6}{-8}\\\\=\frac{3}{4}$

(5,4) & m = (3/4)

y -y1 = m(x-x1)

y - 4 = (3/4)(x - 5)

$y-4=\frac{3}{4}x-\frac{3}{4}*5\\\\y-4=\frac{3}{4}x-\frac{15}{4}\\\\y=\frac{3}{4}x-\frac{15}{4}+4\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{4*4}{1*4}\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{16}{4}\\\\y=\frac{3}{4}x+\frac{1}{4}$

7 0

3 years ago

The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

8 0

3 years ago

Mr.rodriguez invests half money in land a tenth in stocks and a twentieth in bonds he puts the remaining 35,000 in his savings a

Elena-2011 [213]

Answer: $100,000

Step-by-step explanation:

Land + Stocks + Bonds + Savings = 100%

$\dfrac{1}{2}x$ + 0.1x + $\dfrac{1}{20}x$ + 35,000 = 1.00x

= 0.5x + 0.1x + 0.05x + 35,000 = 1.00x

= 0.65x + 35,000 = 1.00x

35,000 = 0.35x

$\dfrac{35,000}{0.35}=\dfrac{0.35x}{0.35}$

100,000 = x

3 0

3 years ago

Read 2 more answers

Hello could anyone tell me what 12 plus 14 times 2000 divided by 13 is?

sveticcg [70]

The exact answer is 2,165.846153846154
Hope this helpssss :)

5 0

2 years ago

“on the following checking account record, enter the figures and add or subtract them to keep the running total correct”

oksano4ka [1.4K]

The running total is $95.27.

There are two types of records, Active and Inactive. There are also two major classifications, Vital and Important.

<h3>Why is record keeping important?</h3>

In order to create reliable financial statements, you need good records. These consist of balance sheets and income (profit and loss) statements. These statements might assist you in managing your business and dealing with your bank or creditors.

He opened the account with $299.88. He subsequently wrote many cheques, from which you deduct the sum of 299,88.

He deposited a check, thus 299.88-90.48= 209.40, 209.40 - 65.00= 144.40, and then he added $381.33 to 144.40 to get 525.73.

then you need to deduct more since he wrote more checks.

Consequently, 525.73-54.47=471.26, and 471.26-375.99=95.27, giving him a balance of $95.27.

Good Records entail documents comprising recorded data that show the efficacy of the quality management system, independent of the format or feature.

To learn more about record keeping refer to:

brainly.com/question/25132652

#SPJ13

6 0

1 year ago

Read 2 more answers