Answer:
The research and development plays an important role in the maintenance engineering is that it basically improve the equipment maintainability and reliability.
According to the requirement, the system and the equipment needs to be maintain in the maintenance engineering.
The research and the development basically provide the products and services and also improve the existing products and services of the system in the maintenance engineering.
Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa
9514 1404 393
Answer:
746.7 ft²
Explanation:
You can add them up, or you can take advantage of multiplication to make the repeated addition simpler.
(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²)
= (3)((112.5 ft² +136.4 ft²) = 3(248.9 ft²) = 746.7 ft²
The total area of the decks on the 3 homes is 746.7 ft².
Explanation:
111 even numbers greater than 300 can be formed with the digits 1,2,3,4,5 if repetition of digits in a number is not allowed.
Answer:
Explanation:
given data:
latent heat of fusion 
surface free energy = 0.204 j/m2
meltinf point = 1538 degree celcius
critical radius is given as
activation free energy is given as
