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arsen [322]
2 years ago
15

Help!!

Engineering
2 answers:
dusya [7]2 years ago
8 0
Ok it depends how old it is
Rufina [12.5K]2 years ago
7 0

Explanation:

I mean honestly it depends like how old is it? is it one of the newer generations because a majority of apple products have airtags but their is also the lost my iPhone app so they can track where ever their iPad or iPhone is.

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A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic
DiKsa [7]

Answer:

The answer is below

Explanation:

1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:

n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm

2) The speed of the rotor is the motor speed. The slip is given by:

Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm

3) The frequency of the rotor is given as:

f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz

4) At standstill, the speed of the motor is 0, therefore the slip is 1.

The frequency of the rotor is given as:

f_r=slip*f_s\\f_r=1*60=60\ Hz

6 0
4 years ago
Write a simple calculator program. Your program should ask for three things two whole numbers and an operator in the form of an
vekshin1

Answer:

The solution code is written in Java.

  1.        Scanner input = new Scanner(System.in);
  2.        System.out.print("Enter operator: ");
  3.        String operator = input.nextLine();
  4.        System.out.print("Enter first integer: ");
  5.        int num1 = input.nextInt();
  6.        System.out.print("Enter second integer: ");
  7.        int num2 = input.nextInt();
  8.        int result = 0;
  9.        switch(operator){
  10.            case "+":
  11.               result = num1 + num2;
  12.               break;
  13.            case "-":
  14.                result = num1 - num2;
  15.                break;
  16.            case "*":
  17.                result = num1 * num2;
  18.                break;
  19.            case "/":
  20.                result = num1 / num2;
  21.                break;
  22.            default:
  23.                System.out.println("Invalid operator");
  24.        }
  25.        System.out.println(result);

Explanation:

To ask for the user input for two whole numbers and an operator, we can use Java Scanner class object. Since the input operator is a string, we can use nextLine() method to get the operator string (Line 3). We use nextInt() method to get whole number input (Line 5 & 7).

Next we use the switch keyword and pass the operator into the switch structure to determine which case statement should be executed. For example,  if the input operator is "*" the statement  "<em>result = num1 * num2;</em> " will run and multiply <em>num1</em> with <em>num2. </em>

3 0
4 years ago
What educational degree does an engineering technologists hold
Pavlova-9 [17]
Engineer technicians typically hold a two-year associates degree, while engineering technologists likewise hold a bachelors degree.
7 0
4 years ago
Compare and contrast the roles of agricultural and environmental scientists.
aleksandr82 [10.1K]

Answer:

HUHHHHHH BE SPECIFIC CHILE

Explanation:

ERM IRDK SORRY BOUT THAT

8 0
3 years ago
A venturi meter is to be installed in a 63 mm bore section of a piping system to measure the flow rate of water in it. From spac
Alex Ar [27]

Answer:

Throat diameter d_2=28.60 mm

Explanation:

 Bore diameter d_1=63mm  ⇒A_1=3.09\times 10^{-3} m^2

Manometric deflection x=235 mm

Flow rate Q=240 Lt/min⇒ Q=.004\frac{m^3}{s}

Coefficient of discharge C_d=0.8

We know that discharge through venturi meter

 Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

h=x(\dfrac{S_m}{S_w}-1)

S_m=13.6 for Hg and S_w=1 for water.

h=0.235(\dfrac{13.6}{1}-1)

h=2.961 m

Now by putting the all value in

Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}

A_2=6.42\times 10^{-4} m^2

 ⇒d_2=28.60 mm

So throat diameter d_2=28.60 mm

     

4 0
3 years ago
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