Answer:
Explanation:
a) the steady-state, 1-D incompressible and no energy generation equation can be expressed as follows:
b) For a transient, 1-D, constant with energy generation
suppose T = f(x)
Then; the equation can be expressed as:
where;
= heat generated per unit volume
= Thermal diffusivity
c) The heat equation for a cylinder steady-state with 2-D constant and no compressible energy generation is:
where;
The radial directional term = 
and the axial directional term is 
d) The heat equation for a wire going through a furnace is:
![\dfrac{\partial ^2 T}{\partial z^2} = \dfrac{1}{\alpha}\Big [\dfrac{\partial ^2 T}{\partial ^2 t}+ V_z \dfrac{\partial ^2T}{\partial ^2z} \Big ]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20%5E2%20T%7D%7B%5Cpartial%20z%5E2%7D%20%3D%20%5Cdfrac%7B1%7D%7B%5Calpha%7D%5CBig%20%5B%5Cdfrac%7B%5Cpartial%20%5E2%20T%7D%7B%5Cpartial%20%5E2%20t%7D%2B%20V_z%20%5Cdfrac%7B%5Cpartial%20%5E2T%7D%7B%5Cpartial%20%5E2z%7D%20%5CBig%20%5D)
since;
the steady-state is zero, Then:
![\dfrac{\partial ^2 T}{\partial z^2} = \dfrac{1}{\alpha}\Big [ V_z \dfrac{\partial ^2T}{\partial ^2z} \Big ]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20%5E2%20T%7D%7B%5Cpartial%20z%5E2%7D%20%3D%20%5Cdfrac%7B1%7D%7B%5Calpha%7D%5CBig%20%5B%20V_z%20%5Cdfrac%7B%5Cpartial%20%5E2T%7D%7B%5Cpartial%20%5E2z%7D%20%5CBig%20%5D)
'
e) The heat equation for a sphere that is transient, 1-D, and incompressible with energy generation is:
Answer:
5.328Ibm/hr
Explanation:
Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
for this case we can define the following equation for mass flow using the first law of thermodynamics
where
Q=capacity of the radiator =5000btu/hr
m = mass flow
then using thermodynamic tables we found entalpy in state 1 and 2
h1(x=0.97, p=16psia)=1123btu/lbm
h2(x=0, p=16psia)=184.5btu/lbm
solving
Answer:
B.197 gpm and 12.4 L/s
Explanation:
Given that
Load Q = 404.5 KW
Water inlet temperature= 6.1 °C
Water outlet temperature= 13.9°C
We know that specific heat for water
Now from energy balance
by putting the values
(1 Kg/s = 15.85 gal/min)
We can say that
We know that
12.38=1000 x volume flow rate
So
volume flow rate = 12.38 L/s
So the option B is correct.
1. You get to build cool things for places like nasa.
2. You get paid very well
Hope this helps
I just deleted among us :/
