Answer: 6g^2+9g-6
Step-by-step explanation:(g+2)(6g−3)
=(g+2)(6g+−3)
=(g)(6g)+(g)(−3)+(2)(6g)+(2)(−3)
=6g^2−3g+12g−6
=6g^2+9g−6
Answer:
<em> (1). x = 14 ; (2). 70°</em>
Step-by-step explanation:
<em>(1).</em> m∠ACD = m∠A + m∠B
6x + 2 = (2x + 1) + (3x + 15)
6x - 5x = 14
<em>x = 14</em>
<em>(2).</em> m∠ABC = 180° - m∠CBD = 140°
<em>m∠A</em> = m∠C = 140° ÷ 2 = <em>70°</em>
Answer:
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Step-by-step explanation:
yhhhhh6bbbb h 66yltktktktoitt
This is the answer that I came up with 12x^2-14x-6x+7 this is because the 2x and the 6x are multiplied together and then the 2x and the -7 are as well and the same is true of the -1 and the 6x and the -1 and the -7.
Answer:
- object is moving to the right with constant speed
- object is moving to the left with constant speed
- object was stationary for a while, then started moving to the right with constant speed
Step-by-step explanation:
These graphs are of position, so the slope of the graph is the change of position with time, which is velocity. When the slope is positive, the velocity is positive, meaning its direction is to the right. When the slope is negative, the velocity is negative, meaning its direction is to the left.
When the slope is zero, the object is stationary (not moving). The position remains as it was.
1. The position vs. time curve is a straight line with positive slope. The object is moving to the right with constant velocity.
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2. The position vs. time curve is a straight line with negative slope. The object is moving to the left with constant velocity.
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3. The position vs. time curve is flat for a while, then increasing with constant slope. The object stayed where it was for a while, then began moving to the right (to larger values of x) with constant velocity.
