The equilibrium membrane potential is 41.9 mV.
To calculate the membrane potential, we use the <em>Nernst Equation</em>:
<em>V</em>_Na = (<em>RT</em>)/(<em>zF</em>) ln{[Na]_o/[Na]_ i}
where
• <em>V</em>_Na = the equilibrium membrane potential due to the sodium ions
• <em>R</em> = the universal gas constant [8.314 J·K^(-1)mol^(-1)]
• <em>T</em> = the Kelvin temperature
• <em>z</em> = the charge on the ion (+1)
• <em>F </em>= the Faraday constant [96 485 C·mol^(-1) = 96 485 J·V^(-1)mol^(-1)]
• [Na]_o = the concentration of Na^(+) outside the cell
• [Na]_i = the concentration of Na^(+) inside the cell
∴ <em>V</em>_Na =
[8.314 J·K^(-1)mol^(-1) × 293.15 K]/[1 × 96 485 J·V^(-1)mol^(-1)] ln(142 mM/27 mM) = 0.025 26 V × ln5.26 = 1.66× 25.26 mV = 41.9 mV
Molar Mass of the NO = 14 g/mol + 16 g/mol = 30 g/mol
Number of mols is 2.79 g = 2.79mol/30g/mol = 0.093 mol
Heat released by the decomposition of 0.093 mol = 92.29kj/mol * 0.093 mol = 8.58 kj (you might include a negative sign to indicate tha the heat is released)
Answer: Small molecular structure
Explanation:
> Bromine and Hydrogen are both non-metals, so they hence cannot form ionic compounds and metals. As such, Ionic Lattice and Metallic structure is wrong.
> gaseous Hydrogen Bromide HBr is produced. Giant covalent substances, such as diamond, have very high melting and boiling points. As such, HBr is a small molecular structure, or a simple covalent substance.
Answer:
Na < K < S < Be
Explanation:
Let's work with NA and molar mass of each.
- 1.5 mol of K → should be converted to atoms ( mol . NA)
1.5 mol . 6.02×10²³ = 9.03×10²³ atoms of K
- 64 g of S → should be converted to mol (mass / molar mass). Then, into atoms. (mol . NA)
64 g / 32.06 g/m = 1.99 mol
1.99 m . 6.02×10²³ = 1.20×10²⁴ atoms of S
- 20 g of Be → should be converted to mol (mass / molar mass). Then, into atoms. (mol . NA)
20 g / 9.01 g/m = 2.22 moles
2.22 m . 6.02×10²³ = 1.33×10²⁴ atoms of Be
- 25 g of Na → should be converted to mol (mass / molar mass). Then, into atoms. (mol . NA)
25 g / 23 g/m = 1.08 moles
1.08 m . 6.02×10²³ = 6.54×10²³ atoms of Na