Answer:
a) positive feedback
Explanation:
positive as in increasing
Nucleotides are organic molecules consisting of a nucleoside and a phosphate.
They serve as monomeric units of the nucleic acid polymers – deoxyribonucleic acid (DNA) and ribonucleic acid (RNA), both of which are essential biomolecules within all life-forms on Earth. Nucleotides are obtained in the diet and are also synthesized from common nutrients by the liver.
Nucleotides are composed of three subunit molecules: a nucleobase, a five-carbon sugar (ribose or deoxyribose), and a phosphate group consisting of one to three phosphates. The four nucleobases in DNA are guanine, adenine, cytosine and thymine; in RNA, uracil is used in place of thymine.
Nucleotides also play a central role in metabolism at a fundamental, cellular level. They provide chemical energy—in the form of the nucleoside triphosphates, adenosine triphosphate (ATP), guanosine triphosphate (GTP), cytidine triphosphate (CTP) and uridine triphosphate (UTP)—throughout the cell for the many cellular functions that demand energy, including: amino acid, protein and cell membrane synthesis, moving the cell and cell parts (both internally and intercellularly), cell division, etc.
Learn more about nucleoside at:
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Answer:
either i have no brain or im over thinking it
Explanation:
Answer:
resend again that question dear
Answer:
Explanation:
1. First, you want to break up the aqueous solutions into their respective ions (remember to write the charge and number of each element). Note that you can only do this to compounds marked as <em>aqueous</em>, so leave the solid be.
(Technically, both Potassium ions would have a coefficient of 6. I am leaving them as they were originally just for ease)
2. Now, you want to get rid of compounds on each side that are the same. These are called spectator ions, and they are exactly as the name says: they simply "spectate" the reaction, meaning they can be removed from the complete ionic equation.
Both the sulfate and potassium ions would be considered spectator ions and would be canceled out. Once removed the equation would look like:
3. The complete ionic equation would be:
