Question

Write the standard equation of the circle below.

Answer 1

Answer:

Choice  1 is correct answer.

Step-by-step explanation:

Since , we know that

(x-a)²+(y-b)² = r² is equation of circle Where r is radius of circle and (a,b) is center of circle.

From diagram , we notice that

center of circle is (a,b) = (-1,2)

Radius is 1.

a = -1 and b =2   and r = 1

Putting above values in equation of circle, we have

(x-(-1))²+(y-(2))² = (1)²

simplifying

(x+1)²+(y-2)² = 1   which is the answer.

Answer 2

Answer:

$(x+1)^{2} +(y-2)^{2} =1$

Step-by-step explanation:

we know that

the equation of the circle into center radius form is equal to

$(x-h)^{2} +(y-k)^{2} =r^{2}$

where

r is the radius of the circle

(h,k) is the center of the circle

In this problem we have

$(h,k)=(-1,2)$

$r=1\ units$

substitute

$(x+1)^{2} +(y-2)^{2} =1^{2}$

$(x+1)^{2} +(y-2)^{2} =1$