Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
Answer:
1/21
Step-by-step explanation:
2/7 ÷ 6 =
2/7 x 1/6 = 2/42
Simplify by dividing the numerator and denominator by 2
1/21
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X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
89 rooms should be set for early book customer
Step-by-step explanation:
According to the given data we have the following:
OVERAGE(CO) = 200
SHORTAGE(CS) = 500
In order to calculate how many rooms should be set for early book customer we would have to use the following formula:
OPTIMAL BOOKING = MEAN + (Z * STDEV)
MEAN = 75
STDEV = 25
SERVICE LEVEL= CS / (CS + CO) = 500 / (500 + 200) = 0.7143
Z VALUE FOR 0.7143 = 0.57
OPTIMAL BOOKING = 75 + (0.57 * 25) = 89
89 rooms should be set for early book customer
