There would be 3 left but fish can't drown so there's 6 left
Hope I helped!
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
x = 6
Option A.
Step-by-step explanation:
We know that
If A, B and C are collineal points, they all pass through a common line.
<--------------14-------------->
A-----------B----------------C
<-----x-----><------x+2---->
Based on the problem and the diagram above,
(x) + (x+2) = 14
(2x+2) = 14
(2x) = 12
(x) = 6
I drew a picture for you. It's below ^.^
Answer:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
Step-by-step explanation:
Suppose that we have a cube with sidelength M.
if we rescale this measure with a scale factor 8, we get 8*M
Now, if previously the area of one side was of order M^2, with the rescaled measure the area will be something like (8*M)^2 = 64*M^2
This means that the ratio of the surfaces/areas will be 64.
(and will be the same for a pyramid, a rectangle, etc)
Then the correct options will be the ones related to surfaces, that are:
The scaled surface area of a square pyramid to the original surface area.
The scaled area of a triangle to the original area.
