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AnnZ [28]
2 years ago
10

The United Van Lines moving company has a truck filled for deliveries to five different sites. If the order of the deliveries is

randomly selected, what is the probability that it is the shortest route?
Mathematics
1 answer:
Scrat [10]2 years ago
7 0

Answer:

0.8333%

Step-by-step explanation:

Assuming that there is only one possible shortest route, the probability that a randomly selected route is given by one divided by the permutation of the order of five different sites:

P=\frac{1}{\frac{5!}{(5-5)!}}=\frac{1}{5*4*3*2*1}\\ P=0.008333=0.8333\%

There is a 1 in 120 chance, or 0.8333% chance that a randomly selected route is the shortest possible route.

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!!!Quick!!! Barbara can walk 3200 meters in 24 minutes. How far can she walk in 3 minutes? (In Meters)
suter [353]

Answer:

400 meters

Step-by-step explanation:

First, divide 3,200 by 24 to find the rate, which is 133.3 (repeated).

Now, multiply 133.3 by 3, which is your answer! 133.3*3=399.9. 399.9 is extremely close to 400, so we can just round it to that.

Hope this helps you out and have a wonderful day (✿◡w◡)

5 0
2 years ago
Please help solve!!! Thank you!!
Hatshy [7]
3 radical 11 ?? Maybe ??
5 0
2 years ago
h(x)=x 2 −1h, left parenthesis, x, right parenthesis, equals, x, squared, minus, 1 Over which interval does h hh have a negative
Semenov [28]

Answer:

(C)−3 ≤ x ≤ 1

Step-by-step explanation:

The average rate of change of function h over the interval a \leq x\leq b, is given by this expression:

\dfrac{h(b)-h(a)}{b-a}

Given the function h(x)=x^2-1 on the interval:− 3 ≤ x ≤ 1

h(1)=1^2-1=0\\h(-3)=(-3)^2-1=9-1=8

The average rate of change:

\dfrac{h(b)-h(a)}{b-a}=\dfrac{0-8}{1-(-3)}=\dfrac{-8}{4}=-2

Therefore, the function has a negative average rate of change over the interval − 3 ≤ x ≤ 1.

CHECK:

(A)Average rate of change of h(x) over the interval − 3 ≤ x ≤ 5=2

(B)Average rate of change of h(x) over the interval 1 ≤ x ≤ 4=5

(D)Average rate of change of h(x) over the interval − 1 ≤ x ≤ 5=4

5 0
3 years ago
What is the probability that in a class of 20 students, 2 of them will have the same birthday?
earnstyle [38]
There would be a 10% chance that they would have the same birthday
8 0
3 years ago
It is estimated that 91% of senior citizens suffer from sleep disorders and 9% suffer from anxiety. Moreover, 6% of seniors suff
Fofino [41]

The probability of senior citizens suffer from sleep disorders is

P(A)=0.91

The probability of senior citizens suffer from anxiety is,0.09.

P(B)=0.09

The probability of seniors suffer from both sleep disorders and anxiety is,

P(A\cap B)=0.06

a. The probability that a senior citizen suffers from anxiety, given that he or she has a

sleep disorder.

P(A|B)=\frac{P(A\cap B)}{P(B)}P(A|B)=\frac{0.06}{0.09}P(A|B)=0.67

8 0
1 year ago
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