Find the sum of the first 3 terms of a geometric sequence with a=96 and r=1/4 the sum is____.
1 answer:
For Geometric sequence, the next term is multiplied by the common ratio.
Common ratio, r = 1/4
1st term, a = 96
2nd term = ar = 96*1/4 = 24
3rd term = ar² = 96*(1/4)*(1/4) = 6
Sum of the first three terms = 96 + 24 + 6 = 126
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