18) 36.36 rounded it is 36.4
22)53.71 rounded it it’s just 53.7
Answer:
Membership decreased by an average of 6,600 people per year from Year 3 to Year 5
Step-by-step explanation:
The average rate of change from Year 3 to Year 5 will be given by the slope of the line joining the points;
(3, 96.8) and (5, 83.6)
The slope of a line given two points is calculated as;
( change in y)/( change in x)
In this case y is the number of members for a given year x.
average rate of change = (83.6-96.8)/(5-3)
= -6.6
Since the number of members is given in thousands, we have;
-6,600
The negative sign implies a decrease in the number of members. Therefore, membership decreased by an average of 6,600 people per year from Year 3 to Year 5
Answer:
The piecewise function is:
Step-by-step explanation:
A piecewise function is a function that is defined in multiple intervals.
In the first interval:
The problem states that a taxi company charges $4.00 for the first mile (or part of a mile).
x is the number of miles. So
If 
.
Second interval:
Here, the cost is defined by a linear function in the following format:
In which 
is the initial price and r is the price paid per mile.
The problem states that each succeeding tenth of a mile costs 80 cents. So
we have the following rule of three.
1 mile - r dollars
0.1miles - 0.8 dollars
So, we have
Piecewise function:
The piecewise function is:
Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.
<h3>What is the area of kite ABDC?</h3>
Formular for the area of a kite is expressed as;
A = pq/2
Where p and q are the two diagonals of the kite.
Given the data in the question;
- Diagonal p = line BC = BM + MC = 3 + 3 = 6
- Diagonal q = line AD = AM + MD
- Line AM = ?
- Line MD = ?
From the diagram, we can determine line AM and line MD using Pythagoras theorem.
c² = a² + b²
First, we find line AM
c² = a² + b²
5² = 3² + b²
25 = 9 + b²
b² = 25 - 9
b² = 16
b = √16
b = 4
Line AM = 4
Next, we determine Line MD
c² = a² + b²
(√58)² = 3² + b²
58 = 9 = b²
b² = 58 - 9
b² = 49
b = √49
b = 7
Line MD = 7
Now, we can find the area of the kite.
Diagonal p = BC = 6
Diagonal q = AD = AM + MD = 4 + 7 = 11
Area = pq/2
Area = [ 6 × 11 ]/2
Area = 66 / 2
Area = 33cm²
Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.
Learn more about area of kite here: brainly.com/question/12286366
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