4,200 people would be on all the blimps
12 - 3x + 4 ( 10 - 2^3 )
12 - 3 ( 2/3 ) + 4 ( 10 - 2^3 )
12 - 2 + 4 ( 10 - 8 )
12 - 2 + 40 - 32
10 + 8
18
Answer:
the probability of inviting both relatives to the meeting = 1/10
Step-by-step explanation:
There are total two invitations that I will send, hence two selections.
For the first selection, I have 5 people total and two of them relatives.
Hence, the probability of inviting relative in first choice is 2/5.
Now assuming that we have invited one relative out of 5 people,
we are left with only 4 people out of which one is relative.
So, probability of inviting relative in second choice is 1/4.
So the probability of inviting both the relatives is (2/5)*(1/4) = 1/10
Answer:
-w^8 (19w-6)
Step-by-step explanation:
1) Factor- −19w^9 + 6w^8
2) Factor and then get the answer which is above.
I hope this is right... ^^
<span>So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel</span>