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Colt1911 [192]
2 years ago
6

A5 inch x 7 inch photograph is placed inside a picture frame. Both the length and width of the frame are 2x inches larger

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0

Answer:

8x+24

dimensions of the photograph  

length - 7 inch  

width - 5 inch

dimensions of the photo frame is 2x larger than both width and length  

length - 7 + 2x

width - 5 + 2x

the perimeter is sum of all 4 sides  

Perimeter = 2(7 + 2x) + 2(5 + 2x)

                = 14 + 4x + 10 +4x

                = 24 + 8x

correct answer is 8x+24

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Question 4 options:
andrew11 [14]

I. The value of x is equal to 8.

II. The dimensions of the rectangle are 13 and 5 inches respectively.

<u>Given the following data:</u>

  • Area of a rectangle = 65 square inches.
  • Length of rectangle = x + 5 inches
  • Width of rectangle = x - 3 inches

To find the value of x, and the dimensions of the rectangle:

Mathematically, the area of a rectangle is given by the formula:

A = LW

Substituting the values, we have:

65 = (x+5)(x-3)\\\\65=x^2-3x+5x-15\\\\65=x^2+2x-15-65\\\\x^2 +2x-80=0\\\\x^2 +10x-8x-80=0\\\\x(x+10)-8(x+10)=0\\\\(x-8)(x+10)=0

x = 8 or x = -10

<u>For the</u><u> length:</u>

when x = 8

Length = 8 +5

Length = 13 inches.

<u>For the</u><u> width:</u>

when x = 8

Length = 8 -3

Length = 5 inches.

Find more information: brainly.com/question/11037225

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2 years ago
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To find a reciprocal of a fraction, switch the numerator and denominator.
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Step-by-step explanation:

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