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taurus [48]
3 years ago
14

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

is virus through the email. There is a 35% chance of receiving it through the webpage. These are not mutually exclusive: the virus enters the system simultaneously by both email and webpage with a probability of 0.17. What is the probability that the virus does not enter the system at all? Enter your answer in decimal form
Mathematics
1 answer:
DedPeter [7]3 years ago
5 0

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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Answer:

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Range: {-1, 5, 9}

Step-by-step explanation:

As the table of the relation is given as follows:

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Domain of a relation consists of all the x-coordinates (first elements) of order pairs.

Range of a relation consists of all the y-coordinates (second elements) of ordered pairs.

So, domain  and range of relation will be as follows:

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<em>Note: If there is any </em><em>duplicate</em><em> element in any x or y-coordinate of any ordered pair, it will be written only </em><em>once </em><em>when we determine domain and range. Here, in this example, 5 is duplicate, so, it will be mentioned only one time when we determine the range of this relation.</em>

Keywords:  domain, relation, range

Learn more about domain and range of a relation from brainly.com/question/11422136

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