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yawa3891 [41]
3 years ago
9

10 cm 12 cm 20 cm 12 + x G 12 cm A X

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

x = 12 cm and y = 24 cm

Step-by-step explanation:

Three sides of the first triangle are 10 cm, 12 cm and 12 cm.

Three sides of second triangle are 20 cm, 12+x cm and y cm.

As these two triangles are similar, it means,

\dfrac{10}{20}=\dfrac{12}{12+x}=\dfrac{12}{y}\\\\\dfrac{1}{2}=\dfrac{12}{12+x}=\dfrac{12}{y}\\\\\dfrac{1}{2}=\dfrac{12}{y}\ \text{and}\ \dfrac{1}{2}=\dfrac{12}{12+x}\\\\y=24\ cm\ \text{and}\ 24=12+x,x=12 cm

So, the value of x is 12 cm and that of y is 24 cm.

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26y and 52y.

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2 years ago
Find x. <br> 2√3<br> 4√3 <br> 8√3 <br> 8
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Answer:

8

Step-by-step explanation:

sin theta = opposite side/ hypotenuse

sin 30 = 4/x

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x sin 30 = 4

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3 years ago
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Yuri computes the mean and standard deviation for the sample data set 12, 14, 9, and 21. He finds the mean is 14. His steps for
Tpy6a [65]

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B. Yuri divided by n instead of n-1

Step-by-step explanation:

It was stated in the question that the dataset was sample dataset. For a sample dataset, the standard deviation is given by the formula,

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Since this is just a sample dataset and not the whole population, Yuri should have divided by n-1 instead of n.

3 0
3 years ago
A bridge is built in the shape of a parabolic arch. The bridge arch has a span of 166 feet and a maximum height of 40 feet. Find
scoray [572]

Answer:

38.27775 feet

Step-by-step explanation:

The bridge has been shown in the figure.

Let the highest point of the parabolic bridge (i.e. vertex of the parabola) be at the origin, O(0,0) in the cartesian coordinate system.

As the bridge have the shape of an inverted parabola, so the standard equation, which describes the shape of the bridge is

x^2=4ay\;\cdots(i)

where a is an arbitrary constant (distance between focus and vertex of the parabola).

The span of the bridge = 166 feet and

Maximum height of the bridge= 40 feet.

The coordinate where the bridge meets the base is A(83, -40) and B(-83, -40).

There is only one constant in the equation of the parabola, so, use either of one point to find the value of a.

Putting A(83,-40) in the equation (i) we have

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\Rightarrow a=-43.05625

So, on putting the value of a in the equation (i), the equation of bridge is

x^2=-172.225y

From the figure, the distance from the center is measured along the x-axis, x coordinate at the distance of 10 feet is, x=\pm 10 feet, put this value in equation (i) to get the value of y.

(\pm10)^2=-172.225y

\Rightarrow y=-1.72225 feet.

The point P_1(10,-1.72225) and P_2(-10,-1.72225) represent the point on the bridge at a distance of 10 feet from its center.

The distance of these points from the x-axis is d=1.72225 feet and the distance of the base of the bridge from the x-axis is h=40 feet.

Hence, height from the base of the bridge at 10 feet from its center

= h-d

=40-1.72225=38.27775 feet.

8 0
2 years ago
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