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Anettt [7]
2 years ago
12

Please solve this...​

Mathematics
1 answer:
pentagon [3]2 years ago
3 0
Slope = (y2 - y1) / (x2 - x1)
Slope = -26 - (-14) / 8-4
Slope = -12 / 4
Slope = -3
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2 years ago
A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long
Pie

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

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Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

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Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

6 0
3 years ago
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