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Svet_ta [14]
4 years ago
10

Find m<4 if m<1 = 100

Mathematics
2 answers:
vlada-n [284]4 years ago
5 0
If <span>m<1 = 100 then since you have 4 of them you will multiply 100 by 4 and get 400.

Your answer: </span><span>m<400

HOPE THIS HELPS! ^_^</span>
Llana [10]4 years ago
4 0
Do you mean m*1? using that as the less then sign makes no sense here. Assuming m*1 = 100, then m=100, so 4m = 100*4 = 400
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How do you do this I have no idea
sveta [45]

Answer:

A

Step-by-step explanation:

Eliminate B C and D

6 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

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5 0
2 years ago
HELLOO!!!!!! HI!!!!!!! CAN U HELP ME?????????
gregori [183]
The solutions are attached

4 0
3 years ago
Can someone please help me ive been stuck in these questions for ages
earnstyle [38]

Answer:

x = 2 (For First question)

Step-by-step explanation:

8^ 1/6 * 2^x = 32^1/2

8^1/6 * 2^x 8^1/6 = 32^1/2/8^1/6

2^x = 32^1/2 / 8^1/6

2^x = 4

2^x = 2^2

x =2

Question 2:

Answer: 50

Step-by-step explanation:

8^1/3/5^-2

= 2/5^-2

= 2/1/5^2

= 2*  5^2/1

= 2 * 5^2

= 2 * 25

= 50

8 0
3 years ago
Plz help ASAP I will mark u branliest
Usimov [2.4K]
Question 2) 6y - 1 = 5
First we need to add 1 to each side.
6y - 1 + 1 = 5 + 1
6y = 6
Then we will divide each side into 6 groups.
6y/6 = 6/6
y = 1

Question 4) 3t - 1 = 8
First we need to add 1 to each side.
3t - 1 + 1 = 8 + 1
3t = 9
Then we will divide each side into 3 groups.
3t/3 = 9/3
t = 3
5 0
3 years ago
Read 2 more answers
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