You can solve the system by isolating the same variable in both equations, then setting those equations equal to each other. For instance, say we isolate y:
Do the same for the other equation, then set both equations equal to each other. You can then solve for x. Once you have a value for x, you can plug it into either of the original equations and find y!
.05*2000=100 Non-Sporting
.06*2000=120 Herding
.24*2000=480 Sporting
.21*2000=420 Working
.16*2000=320 Hound
.16*2000=320 Terrier
.12*2000=240 Tay
Hope I didn't mess up for your sake
Answer:
<u>NOT BOTH BLACK = 1-2/25 = 23/25</u>
Step-by-step explanation:
Bag 1 : 8 non-black out of 10
P(1) = 8/10
Bag 2: 3 non-black out of 10
P(2)=3/5
Probability of both independent events happening can be calculated using the multiplication rule
P(1) and P(2) = P(1)*P(2) = 8/10 * 3/5 = 24/50 = <u>12/25 (both are not black, or none is black)</u>
Interpretating not both black meaning at most one black, then
we calculate the probability of both are black,
P(1) = 2/10
P(2) = 2/5
Probability that both balls are black can be calculated using the multiplication rule
P(1) and P(2) = 2/10 * 2/5 = 2/25
Probability that <u>NOT BOTH BLACK = 1-2/25 = 23/25, i.e. at most one black</u>
<h3>
My answer~</h3>
900.2 or 900 1/5
<h3>
My Step-by-step explanation~</h3>
<em>4501</em> ÷ <em>5</em>
=
<em>900.2</em>
- then convert to fraction or leave as is
<em>900 1/5</em>
<h3><u><em>-------------------------------------------------------------------------------------------------</em></u></h3>
<u><em /></u>
The power of -2 was mistook as 2.
