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3 years ago

A baby grows 4 inches every 6 months. What is his rate of change?

Mathematics

1 answer:

ser-zykov [4K]3 years ago

6 0

Answer:

4:6 but if you reduce it is 2:3

Step-by-step explanation:

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What is 5,307,288 rounded the nearest 100,000

IceJOKER [234]

That's easy it is 5,300,000 I think by the way Might be wrong I hurt my eye so yea don't say I am not good at math it is my eye hurting or it can be 5,300,288

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3 years ago

What is the x intercept of y + 4 =− 4(x − 1)

vivado [14]

Answer:

Step-by-step explanation:

since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.

7 0

2 years ago

If we add 9 tens 5 hundreds and 3 ones then the result is?

ioda

Answer:

9 tens = 90

5 hundreds = 500

3 ones = 3

on adding them we get, 500 + 90 + 3 = 593

6 0

2 years ago

Read 2 more answers

Select all the true statements about the number 3,600−−−−−√.

Paul [167]

Answer:

3,600−−−−−√ is a rational number.I guess

6 0

3 years ago

Read 2 more answers

A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%

IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

$P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18$

a) P(firm will make at least one hire)

$P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32$

Also,

$P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4$

$\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9$

b) expected value and the standard deviation of the number of hires.

$E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58$

$E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89$

7 0

3 years ago