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fiasKO [112]
2 years ago
5

Solve for x: 2xsquared+4x-16=0

Mathematics
1 answer:
sergejj [24]2 years ago
7 0
        2x² + 4x - 16 = 0
2(x²) + 2(2x) - 2(8) = 0
        <u>2(x² + 2x - 8)</u> = <u>0</u>
                  2             2
           x² + 2x - 8 = 0
                          x = <u>-(2) ± √((2)² - 4(1)(-8))</u>
                                               2(1)
                          x = <u>-2 ± √(4 + 32)</u>
                                           2
                          x = <u>-2 ± √(36)
</u>                                       2<u>
</u>                          x = <u>-2 ± 6
</u>                                    2<u>
</u>                          x = -1 ± 3
                          x = -1 + 3    U    x = -1 - 3
                          x = 2                  x = -4
<u />
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<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

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Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

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See step by step explanation below:

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