Answer:
Step-by-step explanation:
Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.
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• The sum of n terms of an AP is
![\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Corange%7B%5Csf%20S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D%20%7D%7D)
• nth term of an AP is given by ,
Answer:
120,000
Step-by-step explanation:
Let's say Rio gets 5x, Kim gets 7x, and Leo gets 3x. In the ratio 5:7:3:1, x = 1
5x + 7x + 3x = total = 15x
3x = 24000
divide both sides by 3 to get x
x = 8000
15x = 8000*15 = 120000
Answer:
.00227 or 5/2197
Step-by-step explanation:
following the basic rules of PEMDAS, we know that we have to solve for the exponent first.
so.... 5/2197
as a decimal, this is .00227...
This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.
