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3 years ago

10

Solve the problem. Make sure your answer is in simplest form and improper fractions are expressed as mixed numbers. A packer fil

ls 7 1/3 boxes in 1 hour. How many boxes can the packer fill in 8 1/4 hours? help me plz!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

postnew [5]3 years ago

8 0

Easy! Just multiply 7 1/3 by 8 which leaves you with 58 2/3. Now, that 1/4 is 1/4 of an hour. If you can fill 7 1/3 boxes in 1 hour, how many can you fill in 1/4? 7 1/3 divided by 1/4 is 29 1/3. Add them together. 81 boxes.

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Question 3 (1 point)

Nonamiya [84]

Answer:

I would think Jessica

Step-by-step explanation:

V36-->6 bc 6*6=36

Again, im pretty sure this is your answer not completely positive

5 0

3 years ago

Solve: -7 < 2x+5 < 7

kondor19780726 [428]

Answer:

$- 6 < x < 1$

Step-by-step explanation:

first things first:

$- 7 < 2x + 5 \\ - 7 - 5 < 2x + 5 - 5 \\ - 12 < 2x \\ - 6 < x$

now:

$2x + 5 < 7 \\ 2x + 5 - 5 < 7 - 5 \\ 2x < 2 \\ x < 1$

now the intersection is:

$- 6 < x < 1$

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4 years ago

Use the situation below to complete the table and answer the questions,

Amiraneli [1.4K]

Answer:

t = 13

Step-by-step explanation:

3 months ------ 4500

6 months ------ x

3/6 = 4500/x

cross multiplation:

3x =27000

x = 9000,or we should have just doubled the wages, since the time doubled

3 months ------ 4500

5 months ------ y

3/5 = 4500/y

3y = 22500

y = 7500

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t months -------- 19500

3/t = 4500/19500 = 3/13

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5 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

Can someone please help me on this???I keep messing it up.

Alchen [17]

Answer:

The answer is B

Step-by-step explanation

As it shows in the table each week the amount adds to 75$. in the table it only shows 4 weeks amount. and the question asks you whats the amount going to be in the 7th week . the amount will be 825.

4 0

3 years ago