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iragen [17]
2 years ago
12

Combine like terms to simplify the following polynomial. 5a²b+7ab² +9c+ 11a²b-3ab² - 9c

Mathematics
1 answer:
Andrew [12]2 years ago
6 0

Answer:

5a²b + 7ab² + 9c + 11a²b - 3ab² - 9c

= (5a²b + 11a²b) + (7ab² - 3ab²) + (9c - 9c)

= 16a²b + 4ab²

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Find the final value if £3500 is invested for 6 years at 6.9% p.a. <br><br> Final value = £
gulaghasi [49]

                  = Answer:

Step-by-step explanation:

interest= 3500 * 6 * 6.9* 1/100

                  = 4949

Final value = £ 3500 + 1449

                  = 4949

5 0
3 years ago
Read 2 more answers
What is the x- intercept of -2x+5y=-10?
disa [49]
To find the x-intersept, just set y = 0 into the equation, then solve it for x:

-2x + 5 * 0 = -10

-2x + 0 = -10

-2x = -10

x = (-10)/(-2)

x = 5 <----- this is the answer.


I hope this helps. =)
3 0
3 years ago
Does anyone know how to solve this?
erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
How to solve number 5.
BabaBlast [244]
Larger?...... I dunno
6 0
3 years ago
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