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Dmitriy789 [7]
3 years ago
6

What is the relationship among the numbers and symbols in the expression 24 ÷ (3 + 5)? Choose all answers that are correct. A. T

wenty-four is split into 3 plus 5 parts. B. Twenty-four is split into 3 parts and increased by 5. C. The expression has a value that is 24 times as much as 3 plus 5. D. Twenty-four is divided into the number of groups equal to the sum of 3 and 5.
Mathematics
2 answers:
baherus [9]3 years ago
8 0
D. is the only answer i think is right.

fredd [130]3 years ago
4 0

Answer:

B.

The difference between 14 and 4 is split into 2 parts.

C.

The expression has a value equal to half as much as 14 minus 4.

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We solve 6 + 4

6 + 4 = 10.

Square root of 10:

\boldsymbol { \sqrt{6 + 4} =  \sqrt{10}  }\\&#10;\\&#10;\\&#10;\boldsymbol {  \sqrt{10}l\underline{ \ 3.16227766017}}\\&#10;\boldsymbol {  \underline{- 10}l \ 3.16227766017 \times 3.16227766017 }\\&#10;\boldsymbol { \ \ \ 00}

<span>The square root of 10 is a periodic decimal (decimal that has infinite decimals, worth the redundancy)

 What is that periodic decimal?
</span>
\boxed{\textbf{3.16227766017} \boldsymbol{ \ \Leftarrow }\textbf{Square root of 10}}

<u>REGARDS!</u>
3 0
3 years ago
Which question is a statical question
kolbaska11 [484]

Answer:

B is a statistical question

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5 0
3 years ago
Determine which function has the greatest rate of change over the interval [0, 2].
ruslelena [56]
Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of a:
m= \frac{y_{2}-y_{1}}{x_2-x_1}
m= \frac{4-1}{2-0}
m= \frac{3}{2}
m=1.5
The average rate of change of the function a over the interval [0,2] is 1.5

Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
m=0.5
The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
Here the end points are (0,0.5) and (2,2.5)
m= \frac{2.5-0.5}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function d over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
4 0
3 years ago
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