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anyanavicka [17]

3 years ago

9

How many times will 1/4 go into 2 2/4

2 answers:

Scilla [17]3 years ago

7 0

Well, there are 4 of 1/4 in each whole number. there is two whole numbers, so that makes 8 of 1/4's. Now we add the two in the fraction and we come out with 10. 1/4 can go into 2 2/4 10 times.

aksik [14]3 years ago

4 0

Well you have to divide them since they have the same denominator it will be easy do it's 1/4 ÷ 10/4 (2 2/4) = 10/4 which reduces to 5/2 which is 2 1/2. so now that you have divided you go back to the original question which was how many times came 1/4 go into 2 2/4 which is 10

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It costs 9.95 for 1 ticket to the movies. If 3 people go, how much would the total price of 3 tickets be?

SIZIF [17.4K]

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3 years ago

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Delvig [45]

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Step-by-step explanation:

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3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago

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Shkiper50 [21]

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2 years ago

15 POINTS! PLEASE HELP! BRAINLIEST!

lina2011 [118]

Answer:

D. 15.3%

Step-by-step explanation:

<u>Total number of outcomes:</u>

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<u>Number of combinations of getting 6 heads:</u>

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<u>Required probability is:</u>

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Correct choice is D

7 0

3 years ago

Read 2 more answers