Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer:
No solution
Step-by-step explanation:
You didn't include enough information
A point doesn't have a slope. A line has. You need to find the slope of the line that these 2 points are on. The slope is
(the difference of the 'y' values) divided by (the difference of the 'x' values)
That appears to be zero. It's a horizontal line.