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zheka24 [161]
3 years ago
7

the sum of the three number is 92. the third is 3 times the first, the first number is 7 less than the second. what are the numb

ers?
Mathematics
1 answer:
vichka [17]3 years ago
8 0
Let x represent the first number, y represent the second, and z represent the third.

x + y + z = 92
z = 3x
x = y - 7

Solve x = y - 7 for y.
x = y - 7
x + 7 = y

Fill in y and z so that we only have to worry about x for now.

x + y + z = 92
x + (x + 7) + (3x) = 92
x + x + 7 + 3x = 92
5x + 7 = 92
5x = 92 - 7
5x = 85
x = 85/5
x = 17

Solve for y. 
y = x + 7
y = (17) + 7
y = 24

Solve for z.
z = 3x
z = 3(17)
z = 51

So x = 17, y = 24, and z = 51. 
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A. \frac{27}{19}

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A,  we get 810<209  ... This is false

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= 238>589   ..... This is false

C. \frac{16}{26}>\frac{30}{31}

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