Answer:
the correct answer is 8
Step-by-step explanation:
Answer:
234 times
Step-by-step explanation:
<u>Number of times the number 7 appears in a hundred</u>
7 as units digit (07-17-27 ..... 97): 10 times
7 as tens digit (70-71-72..... 79): 10 times
20 times the digit 7 appears in first one hundred (0-100)
Let's calculate how many times 7 would be as units or tens in 7 hundreds
20X7 = 140 times digit 7 appears until number 699
<u>Now, from 700 to 777</u>
7 as hundreds digit (700-701-702 .... 777): 78 times
7 as tens digit (770-771-772 .... 777): 8 times
7 as units digit (707-717-727....777): 8 times
78 + 8 + 8 = 94 times the digit 7 appears in the range 700 - 777. Plus 140 times
140 + 94 = 234 times
If you are in college, this question is likely done with calculus.
a = 12
k = 0.2
v(x) = 0 at the maximum after differentiation
V(x) = kx(a - x)
The easiest way to do this is to remove the brackets.
V(x) = akx - kx^2 Substitute the constants
V(x) = 12*0.2*x - 0.2x^2
V(x)/dx = 2.4 - 0.4x = 0 at the maximum
2.4 - 0.4x = 0
0.4x = 2.4
x = 2.4/0.4
x = 6
If you don't know any calculus yet, you can do this by completing the square.
Answer:
z =
Explanation:
Inside angles equal to 120
Angles on a straight angel equal to 180
180 - 120 = 69
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>