divide the points by the multiplier 1.9
so 3.8 /1.9 =2
the base score was 2.0
Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Answer:
t=0 and t=5
Step-by-step explanation:
5t = t^2
Subtract 5t from each side
5t-5t = t^2 -5t
0= t^2 -5t
Factor out a t
0= t(t-5)
Using the zero product property
t=0 and t-5 =0
t=0 and t-5+5=0+5
t=0 and t=5
Las funciones trigonométricas se utilizan fundamentalmente en la solución de triángulos
rectángulos, recordando que todo triángulo rectángulo tiene un ángulo de 90° y sus ángulos
interiores suman 180°. La notación que se acostumbra es la siguiente.
90 yards= 3/4 let d be the distance. (3/4)d=90 Then solve by dividing both sides by d.