Answer:
<h2>
204π units²</h2>
Step-by-step explanation:
The lateral area of the cylinder includes both the side and the ends.
The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height: A = 2π(6 units )(11 units) = 132π units².
The area of one end of this cylinder can be found by applying the "area of a circle" formula: A = πr². Here, with r = 6 units, A = π(6 units)² = 36π units². Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.
The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²
Answer:
y=79/73x+644/73
theres the equation, enjoy <3
We know that
cos A=adjacent side angle A/hypotenuse
adjacent side angle A=24 units
hypotenuse=26 units
cos A=24/26-----> 12/13
cos B=adjacent side angle B/hypotenuse
adjacent side angle B=10 units
hypotenuse=26 units
cos B=10/26------> 5/13
the answers are
cos A=12/13
cos B=5/13
cot A=adjacent side angle A/opposite side angle A
adjacent side angle A=24 units
opposite side angle A=10 units
cot A=24/10------> cot A=12/5
cot B=adjacent side angle B/opposite side angle B
adjacent side angle B=10 units
opposite side angle B=24 units
cot B=10/24------> cot B=5/12
Answer:
6
Step-by-step explanation:
4x-12 = x+7
4x-12+12 = x+7+12
4x = x+19
4x-x = x+19-x
3x=19
x = 6
And if we substitute the value of x into the equation 4x-12 = x+7,
we will get 13 = 13 in the end.
Hope this helps :)
