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Semenov [28]
3 years ago
11

Solve using the quadratic formula. Write answers as an exact value and as a decimal rounded to the nearest hundredth.

Mathematics
1 answer:
vichka [17]3 years ago
4 0

Answer:

\frac{-2±\sqrt{3} }{2}

dec form: -0.13

Step-by-step explanation:

You might be interested in
a person invest $1,700 in an account that earns 3.97% annual interest. find when the value of the investment reaches $3,200
olga_2 [115]

Answer:

  16 1/4 years

Step-by-step explanation:

Assuming interest is compounded annually, the account balance (A) after t years will be ...

  A = P(1 +r)^t

  3200 = 1700·1.0397^t

  log(3200) = log(1700) +t·log(1.0397)

  t = (log(3200) -log(1700))/log(1.0397) ≈ 16.247

The account will reach a balance of $3200 after about 16 1/4 years.

___

You may be asked to round your answer to the nearest integer or tenth. We leave that exercise to the student.

5 0
3 years ago
How to solve and what is the answer
TiliK225 [7]
Two ways: 
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1


x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)]  if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6]  but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/-  [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]

7 0
3 years ago
What is the measure of
dimaraw [331]

Answer:

what what is the question

6 0
2 years ago
Estimate 148% of 103
hammer [34]

Answer:

152.44

Step-by-step explanation:

148/100*103=152.44

6 0
3 years ago
Please don’t skip! Urgent! Please just give me the answers to the solution part.
svlad2 [7]

Answer:

you have selected the correct option for the first part

in the second part, the answer is "there is no solution"

in the third part, the answer is "one solution" which is (0 , 1)

brainly it if you found this helpful

8 0
2 years ago
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