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Semenov [28]
3 years ago
11

Solve using the quadratic formula. Write answers as an exact value and as a decimal rounded to the nearest hundredth.

Mathematics
1 answer:
vichka [17]3 years ago
4 0

Answer:

\frac{-2±\sqrt{3} }{2}

dec form: -0.13

Step-by-step explanation:

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This represents a function with a slope of 2 and y-intercept of 1
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Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
the ratio of girls to boys in an astronomy club was 3:2. there were 30 girls. how many total members were there in the club
lakkis [162]

Answer:

Explanation: the ratio 2:4 can be reduced to 1:2, where the number of girls corresponds to the 1 and the number of boys corresponds to the 2. If there are 14 girls, then there must be 28 boys (14 x 2 = 28). Now to get the total number we need to add the total number of boys and girls together. So 14 + 28 = 42

Step-by-step explanation:

5 0
3 years ago
Mike traveled from the school to the mall and then from the mall to the library. Henry traveled from the school to the library.
Natalija [7]

Answer:

12 miles

Step-by-step explanation:

From the graph given :

Mike's travel :

School to Mall= 16 miles

Mall to Library = 30 miles

Total travel = 16 + 30 = 46 miles

Henry's travel :

From school to Library = Hypotenus :

Distance can be obtained using Pythagoras :

Hypotenus = √(opposite² + adjacent²)

Hypotenus = √(30² + 16²)

Hypotenus = √1156

Hypotenus = 34 miles

Difference in Distance covered :

(46 miles - 34 miles) = 12 miles

4 0
3 years ago
Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po
Olegator [25]

The expressions which represents the slope of a tangent to the curve y=\frac{1}{x+1} at any point (x, y) are:

                                ​f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}

Given the function:

f(x)=y=\frac{1}{x+1}

When (x + h), we have:

f(x+h)=y=\frac{1}{x+h+1}

Next, we would find the derivative of f(x):

f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0
2 years ago
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