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BartSMP [9]
3 years ago
9

Given a square with vertices (0,1), (1,0), (0,-1), and (-1,0), what is the perimeter of the square?

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

the perimeter of the square is 4√2

Step-by-step explanation:

With this being a square, we know that the distance from (0, 1) to (1, 0) is

√[ (1)² + (-1)² ], or √2.

There are four line segments, all of length √2, so the perimeter of the square is 4√2.

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Write the slope-intercept form of the equation of each line.
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Answer:

y=-\frac{8}{3} x - 3

Step-by-step explanation:

Slope-intercept form is y = mx + b.

You are given 8x + 3y = -9, so to convert this into slope-intercept form you would solve for y and rearrange the terms (if needed) to follow the format of mx + b.

Start by subtracting 8x from both sides of the equation.

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Divide both sides by 3 to isolate y.

y = -3 - 8/3x

Rearrange the terms so the "x" variable is first.

y = -8/3x - 3

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<u>Format</u>

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