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BartSMP [9]
3 years ago
9

Given a square with vertices (0,1), (1,0), (0,-1), and (-1,0), what is the perimeter of the square?

Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

the perimeter of the square is 4√2

Step-by-step explanation:

With this being a square, we know that the distance from (0, 1) to (1, 0) is

√[ (1)² + (-1)² ], or √2.

There are four line segments, all of length √2, so the perimeter of the square is 4√2.

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What’s the answer of a multiplying polynomials (3x-1) to the second power and (x+6) to the second power
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9x^4+102x^3+253x^2-204x+36 is the result of multiplying (3x-1) to the second power and (x+6) to the second power

<h3><u>Solution:</u></h3>

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\rightarrow ((3x)^2-2(3x)(1)+1^2) \times (x^2+2(x)(6)+6^2)\\\\\rightarrow (9x^2-6x+1) \times (x^2+12x+36)

Multiply each term in first bracket with each term in second bracket

\rightarrow 9x^2(x^2)+(9x^2)(12x)+(9x^2)(36)-6x(x^2)-6x(12x)-6x(36) + x^2+12x+36

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Combine the like terms

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