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elena-s [515]
3 years ago
10

Unit 2: Lesson 6 - Coding Activity 1

Computers and Technology
1 answer:
gogolik [260]3 years ago
4 0

Answer:

easyy

Explanation:10 smaple runs and 2

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Which of the following is the component of the processor that directs and coordinates most of the operations in the computer?A.
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C. control unit.

Explanation:

A processor is a miniaturized central processing unit a in digital system that interconnects and controls the activities of other components in the device.

The components of a microprocessor are the bus, registers, cache memory, arithmetic and logical unit and the central or control unit.

The bus is the transportation medium for all activities in the processor. The registers like the accumulator and the B register are memory locations used to hold the operand of an operation.The cache memory holds data meant for immediate use by the processor. Arithmetic and logical unit carries out the various arithmetic and logical operation in the processor, while the control unit is responsible for handling or managing all activities in the processor.

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3 years ago
The term packet is used fairly generically to refer to protocol data unit (PDU). There are PDU equivalent names in the different
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Bits

Explanation:

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Note that the term packet is the PDU for data in the network layer of the OSI network system.

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3 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

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b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

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t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

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