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4 years ago

Solve the system of equations: y = 2x - 3 y = x2 - 2x - 8

Mathematics

1 answer:

tino4ka555 [31]4 years ago

6 0

Answer:

Step-by-step explanation:

y = 2x - 3 --------------(i)

y = x² - 2x - 8 -----------(ii)

Substitute y = x² - 2x - 8 in equation (i)

x² - 2x - 8 = 2x - 3

x² - 2x - 8 - 2x + 3 = 0

x² - 2x -2x - 8 + 3 = 0

x² - 4x - 5 = 0

x² + 1x - 5x -5 = 0

x(x + 1) - 5(x + 1) = 0

(x + 1)(x - 5) = 0

x + 1 =0 ; x -5 = 0

x = -1 ; x = 5

When x = -1; y =2*(-1) - 3 = -2 -3 = -5

When x = 5; y = 2*5 - 3 = 10-3 = 7

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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Answer:

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3 years ago

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