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MAXImum [283]
4 years ago
12

Solve the system of equations: y = 2x - 3 y = x2 - 2x - 8

Mathematics
1 answer:
tino4ka555 [31]4 years ago
6 0

Answer:

Step-by-step explanation:

y = 2x - 3   --------------(i)

y = x² - 2x - 8 -----------(ii)

Substitute y = x² - 2x - 8 in equation (i)

x² - 2x - 8 = 2x - 3

x² - 2x - 8 - 2x + 3 = 0

x² - 2x -2x - 8 + 3 = 0

x² - 4x - 5 = 0

x² + 1x - 5x -5 = 0

x(x + 1) - 5(x + 1) = 0

(x + 1)(x - 5) = 0

x + 1 =0 ; x -5 = 0

x = -1     ; x = 5

When x  = -1;    y =2*(-1) - 3 = -2 -3 = -5

When x = 5;     y = 2*5 - 3 = 10-3 = 7

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\huge\mathcal\gray{Answer}

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\huge\it\blue{explaination}

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