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fiasKO [112]
3 years ago
10

The variable x varies jointly with y and z. Use x=2, y=4, z=1 to write an equation relating x, y

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

Equation is x=\frac{1}{2}yz and when y=2 and z=4, x will be 4.

Step-by-step explanation:

Given:

x varies jointly with y and z.

It also means x is directly proportional to y and z.

x=2, y =4,z=1

From above values we can compute the equation as.

x=\frac{1}{2}yz\\2= \frac{1}{2} \times 4 \times 1\\2=2

Hence the Equation is x=\frac{1}{2}yz

Now y=2 and z=4 we get.

x=\frac{1}{2}\times 2 \times 4= 4

Hence when y=2 and z=4, x will be 4.

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–24 + 12d = 2(d – 3) + 22 what does e=?
olchik [2.2K]

Answer:

-24 + 12d = 2(d - 3) + 22

-24 + 12d = 2d - 6 + 22

-24 + 12d = 2d + 16

        12d = 2d + 40

        10d = 40

            d = 4

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
10 POINTS + BRAINLIEST ANSWER!!
arsen [322]
<span>4a - j = 7a + 3
4b - k = 7b + 3

None of the answers are true, a b are always b minus.</span>
7 0
3 years ago
Ten times the sum of twice a number six. Please show the steps and explain&lt;333
liberstina [14]

Answer: 120!

Step-by-step explanation:

6 + 6 = 12

12 x 10 = 120

If the sum is twice the sum of 6 you would add 6 twice and then you would multiply 12 times 10.

Hope i helped! <333

8 0
2 years ago
Point A is located at (-4, -13). Point B is located at (-4, 3). What is the distance between point A
12345 [234]

Answer:

the distance is 16

Step-by-step explanation:

Hi there!

We are given point A (-4,-13) and point B (-4,3). We need to find the distance between those two points

the distance formula is given as \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} where (x_{1},y_{1}) and (x_{2}, y_{2}) are points

we are given 2 points, which is what we need for the formula. However, let's label the values of the points to avoid any confusion

x_{1}=-4

y_{1}=-13

x_{2}=-4

y_{2}=3

now substitute those values into the formula. Remember: the formula uses SUBTRACTION.

\sqrt{(-4--4)^2+(3--13)^2}

simplify

\sqrt{(-4+4)^2+(3+13)^2}

now add the values inside the parenthesis that are under the radical

\sqrt{(0)^2+(16)^2}

raise everything under the radical to the second power

\sqrt{0+256}

add under the radical

\sqrt{256}

now take the square root of 256

\sqrt{256}=16

so the distance between point A and point B is <u>16</u>

Hope this helps! :)

8 0
3 years ago
The volume of the triangular prism is 12.5 m³. The length is 2.5 m and the base is 2 m. What is the width?
Fantom [35]

Answer:

  (4)  5 m

Step-by-step explanation:

You want the length of side x of a right triangular prism with base edge lengths of 2.5 m and 2 m, and a volume of 12.5 m³.

<h3>Volume</h3>

The volume of the prism is given by the formula ...

  V = Bh

where B is the area of the base:

  B = 1/2bh . . . . where b and h are the leg dimensions of the right triangle

Using these formulas together, we have ...

  V = 1/2(2.5 m)(2 m)x

  12.5 m³ = 2.5x m²

Dividing by 2.5 m², we find x to be ...

  (12.5 m³)/(2.5 m²) = x = 5 m

The dimension labeled x has length 5 meters.

6 0
9 months ago
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