If possible please help

Find the measure of angle B in isosceles triangle ABC.

jenyasd209 [6]

I think its B)55
i hope it helps

3 0

3 years ago

y = -16x2 + 32x - 10 This parabola has x-intercepts, representing the times when the dolphin's height above water is feet.

Lina20 [59]

Answer: This parabola has 0.3875 x-intercepts,
representing the times when the dolphin's height above water is 
0 feet.

The x-intercept is the point where the graph crosses the x-axis, which is when the value is y=0.
The calculation for y=0 would be
Y = -16x2 + 32x - 10
0 = -16x2 + 32x - 10
-8x2 + 16x - 5=0

-b +-√(b^2-4ac) /2a=
-16 +-√(16^2-4(-8)(-5)) /2(-8) =
-16+- √(256-160/ -16 =
-16+- √(96/ -16 =
-16+- 9.8/ -16 =
x1= 0.3875
x2= -1.6125

6 0

3 years ago

Read 2 more answers

Which vertex will result in the minimum value of the function T = x - 2y?

PilotLPTM [1.2K]

Answer:

the objective function, P, at each vertex ... Example: Find the maximum and minimum values of P=3x+2y subject to x + 4y ≤ 20 ... We can find the intersection of the two lines.

6 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

2 years ago

Which graph could represent a constant balance in a bank account over time? A graph titled Daily Balance. The horizontal axis sh

kramer

Answer:

See the image.

Step-by-step explanation:

Constant balance in a bank account signifies that the balance in the account remains constant throughout time.

That is, it did not rise or diminish with time.

As a result, the graph of such a circumstance is a horizontal line parallel to the Time period axis.

4 0

2 years ago