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gladu [14]
3 years ago
14

Explain why the equation (x-3)^2-38=11 has two solutions. Then solve the equation to find the solutions. Show your work.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
4 0

Answer:

X = 10 and X = -4

Step-by-step explanation:

(x-3)^2-38=11

(x-3)^2 = 11 +38

(x-3) ^2 = 49

Taking square root on both sides

√(x-3) ^2 = √ 49

X-3 = +7, -7

X = 7 +3,    X= -7+3

X = 10        X = -4

So, it has got two solutions

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3 years ago
What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

 y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
3 years ago
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Answer:║

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3 0
3 years ago
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What is the distance between the points (7.8) and (3.9) on a coordinate grid???
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Answer:

3.9

Step-by-step explanation:

if one point is 7.8 and the other is 3.9

you would subtract 7.8 and 3.9

the answer is 3.9 away from each other

6 0
3 years ago
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