pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
times that by 4
4√x
Explain why the equation (x-3)^2-38=11 has two solutions. Then solve the equation to find the solutions. Show your work.
1 answer:
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pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
times that by 4
4√x
Answer:
a) 0.5 = 50% probability that an NPN transistor will be selected.
b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types
c) 66.67% probability that it comes from the cabinet that contains only NPN transistors
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
a) What is the probability that an NPN transistor will be selected?
1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.
1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.
1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.
So
0.5 = 50% probability that an NPN transistor will be selected.
b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?
Here we use the conditional probability formula.
Event A: NPN transistor
Event B: From the third cabinet.
50% probability that an NPN transistor will be selected, so .
1/6 probability that it is from the third cabinet and NPN, so
The desired probability is:
0.3333 = 33.33% probability that it came from the cabinet that contains both types.
c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?
Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So
x + 33.33 = 100
x = 66.67
66.67% probability that it comes from the cabinet that contains only NPN transistors
Answer:
Step-by-step explanation:
A)
the sum of any two sides of a right triangle more than any other side
14+15>29, x is less than 29
14+x>15
x>1
15+x>14
x>-1
1<x<29
lets use Pythagorean Theorem
14^(2)+15^(2)=c^2
196+225=c^2
421=c^2
plusminus sqrt(421)=c
distance can't be negative, so:
c=sqrt(421)
c=20.5182845287
sqrt(421) is the largest possible right triangle side
1<xsqrt(421)
B) as we can see from above, the largest possible length of the third side is 14/sqrt(421) or about 20.5182845287ft
C)sqrt(421) by 14 by 15
tan(x1)=15/14
x1=tan^-1(15/14)
x1=47 degrees
tan(x2)=14/15
x2=tan^-1(14/15)
x2=43 degrees