I think about 644 Tickets just an Educated guess.
Answer:
x= 4,-4
Step-by-step explanation:
IF your equation looks like this :
![\sqrt[3]{x^2-8}=2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2-8%7D%3D2)
50 i’m pretty sure that’s The answer
Answer:
= 2x^4 + 6x^3 - 8x^2 + 24x
= 2x ( 2x^3 + 3x^2 - 4x + 12)
Step-by-step explanation:
(X^2 + x - 6) (2x^2 + 4x) =
Let's open the brackets carefully
x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x
= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x
= 2x^4 + 6x^3 - 8x^2 + 24x
= 2x ( 2x^3 + 3x^2 - 4x + 12)
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
