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Karolina [17]
2 years ago
12

John purchases goods for R450.00 including VAT . Calculate the amount he pays for VAT

Mathematics
1 answer:
Nady [450]2 years ago
8 0

Answer:

Whats the percentage of the VAT?

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Eli has 8 black pens and 5 in his desk drawer. He also has 3 yellow highlighters, 4 green highlighters, and 5 pink highlighters
34kurt

Answer:

The answer is 15/52. (Please make me as brainliest (: )

7 0
3 years ago
I need help finding ac, cb, and ab
Taya2010 [7]
AC is 2x+1
CB is 3x-4
AB= 2x+1+3x-4


6 0
3 years ago
Q # 4 Simplify the product
timama [110]
For this case we have the following product:
 (x-4) (x + 3)

 We must use the distributive property correctly to solve the problem.
 We have then:
 x ^ 2 + 3x - 4x - 12

 Then, we must add similar terms.
 We have then:
 x ^ 2 - x - 12

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8 0
3 years ago
Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?
Archy [21]

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

7 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
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