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faust18 [17]
3 years ago
6

Sorry I just asked another question a few minutes ago The photo cut off the word equation

Mathematics
2 answers:
Scrat [10]3 years ago
7 0

Answer:

x=1

  1. Multiply both sides by 10 (13)10-0.5(2x-6)*10+2x(10)=17*10
  2. Refine 130-5(2x-6)+20x=170
  3. Subtract 300 from both sides
  4. Simplify -5(2x-6)+20x=40
  5. Expand 10x+30=40
  6. Subtract 30 from both sides
  7. Simplify 10x=10
  8. Divide both sides by 10
  9. Simplify x=1
<h2><em>:) Hope you enjoy this :)</em></h2>
Ne4ueva [31]3 years ago
6 0
X=1 is the answer because if you simplify the you would get x=1
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Determine if the following equations form a perpendicular line or not
GREYUIT [131]
  • Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.

If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2

<h2>6.</h2>

Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation: -5y=-2x+8

Next, divide both sides by -5 and your slope-intercept form is y=\frac{2}{5}x+\frac{8}{5}

Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>

<h2>7.</h2>

It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:

6x-3y=15 \\-3y=-6x+15\\y=2x-5\\\\2x+4y=-12\\4y=-2x-12\\y=-\frac{1}{2}x-3

Now since 2 <em>is</em> the negative reciprocal of -1/2, <u>these lines are perpendicular.</u>

5 0
3 years ago
Which property is shown?
hoa [83]
Answer is <span>A. 
associative property 

...................regrouped</span>
7 0
3 years ago
7.2x12x0.23=? Round to the nearest hundredth
g100num [7]
The answer would be 19.87
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3 0
3 years ago
Element X is a radioactive isotope such that its mass decreases by 67% every year. If
sattari [20]

Answer:

Step-by-step explanation:

X is mass which I s decrease. If you have 740 grams of element x and you add the function.per the rate day you will have a hundredth percent.

8 0
3 years ago
A truck is traveling at 74.5 kilometers per hour away from you. The driver is blowing the horn which has a frequency of 415 Hz.
Sphinxa [80]
<span>fo = 335 Hz</span>let fo = frequency heard 
<span>f = actual frequency </span>
<span>v= speed of sound </span>
<span>vs = speed of source </span>

<span>For the first one, </span>
<span>fo = fv/(v - vs) </span>
<span>74.5 km/h = 20.69 m/s </span>
<span>vs = -20.69m/s since it is moving away from you </span>

<span>fo = (415Hz)(346m/s)/(346m/s - (-20.69m/s)) </span>
<span>fo = 392 Hz </span>

<span>For the second one, </span>
<span>fo = fv/(v - vs) </span>
<span>82.8 km/h = 23 m/s </span>
<span>vs = 23m/s </span>

<span>fo = (312Hz)(331m/s)/(331m/s - (23m/s)) 
</span>
5 0
3 years ago
Read 2 more answers
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