Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

is the algebraic representation for an exponential function
Step-by-step explanation:
Given:
f(x + 1) = 4.f(x)
f(3) = 16
To Find:
Algebraic representation for an exponential function=?
Solution:
From the formula f(x+n) =
f(x)
when n= 1, x= 3
f(3+1)= 4(1)f(3)
f(4)= 4f(3)
Substituting the value of f(3)
f(4)= 4f(3)
f(4)= 4 x 16
f(4)= 64
f(4)=
f (5) =
x 16
f (5) =
x
f(5)= 
Similarly,
F(6) = 
Hence, 
<span>the circumstances of a circle with a diameter of 30 centimeters
</span>The answer is 94.2 centimeters
<span>
Hope it helps c:</span>
48 divided by 2 = 24
3333 divided by 6 = 555.5
2/7 ( k+5/8) = 2 and 2/7
2/7 (k+5/8) = 16/7 |multiply by 7
2(k+5/8) = 16 |divide by 2
k+5/8 = 8 |subtract 5/8
k=8-5/8 = 7 and 3/8 = 27/8 = 7.375