Determinati numerele de trei cifre care,suprimand cifra zecilor, obtinem un numar de 13 ori mai mic.

Tiara earned 12 dollars on her

Fantom [35]

Answer:

C

Step-by-step explanation:

12 + 3x

12 + 3(20)

12 + 60

72

7 0

2 years ago

Julio has 1000 square ft of living space. The n he added a room that was 20 ft by 10 ft. What was the percentage increase of liv

Gemiola [76]

Answer:

Step-by-step explanation:mmmmmmm

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative

$-2$ -> neagtive

$-1\leq x$ -> neagtive

$x>2$ -> positive

Therefore, the solution to the inequality is the following;

$x>2$

6 0

2 years ago

Please help me find the area of this irregular shape.

ANTONII [103]

Answer:

23 Cm(2)

Step-by-step explanation:

Sincerest Apologies if it is incorrect

if it's not 23 it may be:

26 Cm(2)

6 0

2 years ago

Micah walks on a treadmill at 4 miles per hour. He has walked 2 miles

lana66690 [7]

<span>Let time taken by Luke to cover the distance = x hours Speed of Luke = 6 miles per hour Therefore, Distance covered by Luke = 6x ------(1) Speed of Micah = 4 miles per hour Since Micah walked 2 miles before Luke started running, Luke started 1/2 an hour after Micah started. Therefore time taken by Micah to cover the distance = x+1/2 Distance covered by Micah = 4(x + 1/2) -------(2) Equating (1) and (2) 6x = 4(x+1/2) 6x = 4x +2 2x = 2 x= 1 Therefore Luke would take 1 hour to cover the distance covered by Micah.</span>

6 0

3 years ago