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vredina [299]
4 years ago
9

Let j = 32. What is the value of j + 12? A. 12 B. 20 C. 44 D. 50

Mathematics
2 answers:
nignag [31]4 years ago
8 0
44 because 32+12=44.
Travka [436]4 years ago
5 0
The answer ic C 44 yep
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Write an equation of the line that has a slope of -5 and a y- intercept of 4 in a slope intercept form.
Anastasy [175]

Answer:

y=-5x+4

Step-by-step explanation:

7 0
3 years ago
HELPPPPP PLEASEEEEE!!!
Pepsi [2]

Answer:

The height of right circular cone is h = 15.416 cm

Step-by-step explanation:

The formula used to calculate lateral surface area of right circular cone is: s=\pi r\sqrt{r^2+h^2}

where r is radius and h is height.

We are given:

Lateral surface area s = 236.64 cm²

Radius r = 4.75 cm

We need to find height of right circular cone.

Putting values in the formula and finding height:

s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2}  \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416

So, the height of right circular cone is h = 15.416 cm

4 0
3 years ago
Andre drew a plan of the courtyard at a scale of 1 to 60 on his drawing one side of the courtyard is 2.75 inches what is the act
Furkat [3]

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165 inches

Step-by-step explanation:

The scale is 1 to 60, so real measurements are 60 times bigger than drawing measurements.

2.75 inches * 60 = 165 inches

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
Express 10500 in term if it's prime factor
Shkiper50 [21]
2 |  10500
2 !    5250
3 |     2625
5 |       875
5 |       175
5 |         35
             7
The prime factors are  2*2*3*5*5*5*7 or 2^2*3*5^3*7

3 0
3 years ago
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