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Pepsi [2]
3 years ago
9

-97/7=x-5/7x PLEASE HURRY

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

The answer is x=-48.5. Hope this helps

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Which algebraic expression is a polynormal
katrin [286]

Answer:

Step-by-step explanation:

Polynomials in one variable are algebraic expressions that consist of terms in the form a x n a x n where n is a non-negative (i.e. positive or zero) integer and a is a real number and is called the coefficient of the term. The degree of a polynomial in one variable is the largest exponent in the polynomial

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3 years ago
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4x/3=8 what is x? PLEASE HURRY DUE TOMORROW!!!!!!
DENIUS [597]

Step-by-step explanation:

4x=3×8

4x=24

x=24÷4

x=6

7 0
3 years ago
I'll give BRAINIEST<br><br> .............
Andrew [12]
Its 0.25. ez. i hope i helped :)

3 0
3 years ago
A model rocket is launched with an intitial upupward velocity of 202 ft/s. The rocket’s height h (in feet) after seconds is give
dsp73

Given that the height of a object thrown within a gravitational field is given as a quadratic equation in time, <em>t</em>, the time at which the object is at a specified height can be found by the quadratic formula

The values of, <em>t</em>, for which the height of the rocket is 82 feet are;

t = 12.21 seconds or t = 0.42 seconds

Question: <em>Parts of the question that appear missing but can be found online are (i) To find the values of the time, t, when the rocket's height is 82 feet and round answers to the nearest hundredth</em>

The known parameters of the rocket are;

The initial upward velocity of the rocket, v = 202 ft./s

The given function representing the height, <em>h</em>, (in feet) after <em>t</em> seconds is presented as follows;

H = 202·t - 16·t²

The unknown;

The time for which the height of the rocket is 82 feet

Method;

Substitute H = 82 feet in the height function equation and solve for <em>t</em> as follows;

When H = 82, we get;

82 = 202·t - 16·t²

Therefore;

16·t² - 202·t + 82 = 0

Dividing the above equation by <em>2</em> gives;

(16·t² - 202·t + 82)/2 = 0/2

8·t² - 101·t + 41 = 0

By using the quadratic formula, we get;

\mathbf{t = \dfrac{101 \pm \sqrt{(-101)^2 - 4 \times 8 \times 41} }{2 \times 8}  =  \dfrac{101 \pm \sqrt{8889} }{16}}

Therefore, the values of <em>t</em> given by rounding off to the nearest hundredth are;

t = 12.21 or t = 0.42

The values of the time, <em>t</em>, at which the height of the rocket is 82 feet are t = 12.21 seconds or t = 0.42 seconds

Learn more about equation models of height as a function of time here;

brainly.com/question/84352

7 0
3 years ago
3(2x - 4) + x = 9<br> help with homework
natita [175]

6x - 12 + x = 9

6x + x - 12 = 9

Collect like terms

7x - 12 = 9

Add both sides 12

7x - 12 + 12 = 9 + 12

7x = 21

Divide both sides by 7

7x ÷ 7 = 21 ÷ 7

x = 3

7 0
3 years ago
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