Given:

x lies in the III quadrant.
To find:
The values of
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,




x lies in the III quadrant. So,


Now,



And,





We know that,



Therefore, the required values are
.
AC is parallel to MN then triangle ABC and triangle MBN are similar and the ratio of the corresponding sides are equal...
8x + 3× + 9x = 180
20x = 180
x = 180/20
x = 9
The smallest angle is: 3×9 = 27 degrees
Note: 180 degrees is the sum of angles in a triangle
Answer: 
Step-by-step explanation:
Here the total numbers are 1, 4, 3, 7, 6
Since the total number of possible arrangement =
The total number of the odd numbers in the given numbers = 3
Thus the possible arrangement that the first three digits will be odd numbers = 
Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement =
= 
multiply 40 by 3/4
40 x 3/4 = 40*3 = 120, 120/4 = 30
he answered 30 correctly
40-30 = 10, he missed 10