Answer:
b=2p+6
Step-by-step explanation:
Let the number of bundles of palm leaves : b
Let the number of occupants : p
We are asked to Translate the sentence given below into an equation.
Six more than twice the number of occupants is equal to the number of bundles.
i)6 more means : +6
ii)twice the number of occupants : 2p
iii) Number of Bundles : b
Hence
b=2p+6
Answer: 34/24
Step-by-step explanation:
B. 1.67
m : n = 2 : 1
( x, y ) = ( (1*3 + 2*(-2))/(2+1) ; (1 * (-1) + 2 * 3) /(2 + 1) ) =
= ( (3-4)/3 ; (-1+6)/3 ) 1.67
Answer:
a)![0.0299\leq \widehat{p}\leq 0.0640](https://tex.z-dn.net/?f=0.0299%5Cleq%20%5Cwidehat%7Bp%7D%5Cleq%200.0640)
b)Yes
Step-by-step explanation:
n = 593
x = 28
![\widehat{p}=\frac{x}{n}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp%7D%3D%5Cfrac%7Bx%7D%7Bn%7D)
![\widehat{p}=\frac{28}{593}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp%7D%3D%5Cfrac%7B28%7D%7B593%7D)
![\widehat{p}=0.047](https://tex.z-dn.net/?f=%5Cwidehat%7Bp%7D%3D0.047)
Confidence level = 95%
So,
at 95% = 1.96
Formula of confidence interval of one sample proportion:
=![\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}](https://tex.z-dn.net/?f=%5Cwidehat%7Bp%7D-Z_%5Calpha%20%5Csqrt%7B%5Cfrac%7B%5Cwidehat%7Bp%7D%281-%5Cwidehat%7Bp%7D%7D%7Bn%7D%7D%5Cleq%20%5Cwidehat%7Bp%7D%5Cleq%20%5Cwidehat%7Bp%7D%2BZ_%5Calpha%20%5Csqrt%7B%5Cfrac%7B%5Cwidehat%7Bp%7D%281-%5Cwidehat%7Bp%7D%7D%7Bn%7D%7D)
=![0.047-(1.96)\sqrt{\frac{0.047(1-0.047)}{593}}\leq \widehat{p}\leq 0.047+(1.96)\sqrt{\frac{0.047(1-0.047}{593}}](https://tex.z-dn.net/?f=0.047-%281.96%29%5Csqrt%7B%5Cfrac%7B0.047%281-0.047%29%7D%7B593%7D%7D%5Cleq%20%5Cwidehat%7Bp%7D%5Cleq%200.047%2B%281.96%29%5Csqrt%7B%5Cfrac%7B0.047%281-0.047%7D%7B593%7D%7D)
=![0.0299\leq \widehat{p}\leq 0.0640](https://tex.z-dn.net/?f=0.0299%5Cleq%20%5Cwidehat%7Bp%7D%5Cleq%200.0640)
Hence a 95 percent confidence interval for the proportion of all new websites that were anonymous is ![0.0299\leq \widehat{p}\leq 0.0640](https://tex.z-dn.net/?f=0.0299%5Cleq%20%5Cwidehat%7Bp%7D%5Cleq%200.0640)
b) May normality of p be assumed?
Condition for normality : np>10 and np(1-p)>10.
and ![0.047\cdot593(1-0.047)>10](https://tex.z-dn.net/?f=0.047%5Ccdot593%281-0.047%29%3E10)
27.871 and 26.561063
Hence p is assumed to be normal since the condition is satisfied